(Procedure) CBSE: National Eligibility Test (NET) "December 2014"
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NATIONAL ELIGIBILITY TEST (NET) "DECEMBER 2014"
CENTRAL BOARD OF SECONDARY EDUCATION
:: Procedure & Criteria For Declaration of Result ::
This will comprise of following steps:
Step I: Minimum marks to be obtained in NET for considering a candidate for the award of JRF and eligibility for Assistant Professor:
The candidates are required to obtain following minimum marks separately in Paper-I, Paper-II and Paper-III as given below
| CATEGORY | Minimum Marks (%) to be obtained | ||
| PAPER – I | PAPER – II | PAPER – III | |
| GENERAL | 40 (40%) | 40 (40%) | 75 (50 %) |
| OBC(Non-creamy layer)/ PWD/ SC/ ST | 35 (35%) | 35 (35%) | 60 (40 %) |
Step II: Amongst those candidates who have cleared step I, a merit list will be prepared subject-wise and category-wise using the aggregate marks of all the three papers secured by such candidates.
Step III: Top 15% candidates (for each subject and category), from the merit list mentioned under step II, will be declared NET qualified for eligibility for Assistant Professor only.
Step IV: A separate merit list for the award of JRF will be prepared from amongst the NET qualified candidates figuring in the merit list prepared under step III.